Physics > Superposition of Waves > 2.0 Interference of Waves
Superposition of Waves
1.0 Introduction
2.0 Interference of Waves
2.1 Relation between phase difference $\left( \phi \right)$ and path difference $\left( {\Delta x} \right)$
2.2 Interference of waves from coherent sources
2.3 Interference of waves from incoherent sources
2.4 Reflection and transmission of a wave
2.5 Motion of wave during reflection
2.6 Expression for the reflection and transmission of wave
3.0 Standing or Stationary Wave
3.1 Transverse stationary wave on a stretched string
3.2 Vibrations in a stretched string
3.3 Melde's Experient
3.4 Resonance
4.0 Longitudinal stationary wave in an organ pipe
4.1 Open organ pipe
4.2 Closed organ pipe
4.3 End correction
4.4 Resonance tube
4.5 Energy in a stationary wave
5.0 Beats
6.0 Questions
2.1 Relation between phase difference $\left( \phi \right)$ and path difference $\left( {\Delta x} \right)$
2.2 Interference of waves from coherent sources
2.3 Interference of waves from incoherent sources
2.4 Reflection and transmission of a wave
2.5 Motion of wave during reflection
2.6 Expression for the reflection and transmission of wave
3.2 Vibrations in a stretched string
3.3 Melde's Experient
3.4 Resonance
4.2 Closed organ pipe
4.3 End correction
4.4 Resonance tube
4.5 Energy in a stationary wave
1. Mathematically the phase difference between two different points $P$ and $Q$ separated by a distance $\left( {\Delta x} \right)$ is given by, $$\phi = \left( {\frac{{2\pi }}{\lambda }} \right)\Delta x$$ where,
$\phi $: Phase difference
$\Delta x$: Path difference
$\lambda $: Wavelength of wave
2. The phase difference between two waves generated by the same source when they travel along different path.
Lets the path difference between the two waves be $\Delta x$. Then the corresponding phase difference is given by, $$\phi = \left( {\frac{{2\pi }}{\lambda }} \right)\Delta x\quad or\quad \phi = k\Delta x$$
3. The phase difference at any point at two different time $t_1$ and $t_2$ $\left( {{t_2} > {t_1}} \right)$ is given by,$$\phi = \left( {\frac{{2\pi }}{T}} \right)\Delta t\quad or\quad \phi = \omega \Delta t$$ where
$\Delta t = {t_2} - {t_1}$
$\omega $: angular frequency
4. When a wave splits equally in two parts at point $A$ and travel along different path.
At point $B$, where the waves combine, there is a phase difference because of the path difference.
If $\lambda $ is the wavelength and $\Delta x$ is the path difference. Then the phase difference can be written as, $$\phi = \left( {\frac{{2\pi }}{\lambda }} \right)\Delta x$$